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**Lower Triangular Matrix by Column Major Mapping in C and C++:**

In this article, I am going to discuss **Lower Triangular Matrix by Column Major Mapping in C and C++** Language with Examples. Please read our previous article, where we discussed **Lower Triangular Matrix by Row-Major Mapping in C and C++** Language with Examples.

**Lower Triangular Matrix by Column Major Mapping:**

Now let us look at the column-major formula and store the elements column by column in a single dimension. This is the matrix that we want to store in a single dimension array.

We have to create an array of size **15 **or we can calculate the size of the array by using the below formula: **= n * (n +1) / 2.**

Here we have created an array of size 15. Now we have to insert elements of the matrix by column-major mapping.

**1**^{st} Column:

^{st}Column:

**2**^{nd} Column:

^{nd}Column:

**3**^{rd} Column:

^{rd}Column:

**4**^{th} Column:

^{th}Column:

**5**^{th} Column:

^{th}Column:

So, we have filled elements column by column but there must be some formula to map these elements from a two-dimensional matrix to a single dimension array. For that, we will take some examples and we will do some observation and then we will prepare the formula for it. Let us take an example **M [4][4]**:

**M [4][4]** is present on the **12 ^{th}** index in the array. So, we have to find

**Index (M [4][4])**.

We have to reach on 4^{th} column to find the target element. So, we need to skip 3 columns to reach the 4^{th} column.

So, 1^{st} column having **5** elements: **Index (M [4][4]) = 5 +**

2^{nd} column having **4** elements: **Index (M [4][4]) = 5 + 4 +**

3^{rd} column having **3** elements: **Index (M [4][4]) = 5 + 4 + 3**

We have skipped 3 columns â€˜1â€™, â€˜2â€™ and â€˜3â€™.

Now we are pointing at the beginning of the 4^{th} column. Do we have to move ahead to get on the element? No, we are on the element. So,

**Index (M [4][4]) = [5 + 4 + 3] + 0**

**Index (M [4][4]) = 12**

We got 12 here. So, this is true. Next, we want the element **M [5][4] **which is in the same column as the previous element **M [4][4].** Let us get the index for **M [5][4]**. This is again in the fourth column.

For reaching the 4^{th} column, again we have to skip **3** columns â€˜1â€™, â€˜2â€™ and â€˜3â€™. So, the expression will be: **Index (M [5][4]) = 5 + 4 + 3**

Now how much we should move ahead? Just one element we should move forward. So, add 1 to the above expression.

**Index (M [5][4]) = [5 + 4 + 3] + 1**

How this can be converted into the formula for any index? By observing previous example, for any **Index (M [i][j])** formula will be:

**Index (M [i][j])** = **[n * (j â€“ 1) â€“ (j â€“ 2)(j â€“ 1)/2] + (i â€“ j)**

Where **n** is the dimension of the matrix, **i** is the row number, and **j** is the column number. Now letâ€™s look at the code part:

**Lower Triangular Matrix by Column Major Mapping Code in C Language:**

#include <stdio.h> #include <stdlib.h> struct Matrix { int *B; int n; }; void Set(struct Matrix *m, int i, int j, int y) { if (i >= j) m->B[(m->n * (j - 1) - (j - 2) * (j - 1) / 2) + (i - j)] = y; } int Get(struct Matrix m, int i, int j) { if (i >= j) return m.B[(m.n * (j - 1) - (j - 2) * (j - 1) / 2) + (i - j)]; else return 0; } void Display(struct Matrix m) { int i, j; printf ("\nMatrix is: \n"); for (i = 1; i <= m.n; i++) { for (j = 1; j <= m.n; j++) { if (i >= j) printf ("%d ", m.B[(m.n * (j - 1) - (j - 2) * (j - 1) / 2) + (i - j)]); else printf ("0 "); } printf ("\n"); } } int main() { struct Matrix M; int i, j, y; printf("Enter Dimension of Matrix: "); scanf("%d", &M.n); M.B = (int *) malloc (M.n * (M.n + 1) / 2 * sizeof(int)); printf("Enter all the elements of the matrix:\n"); for (i = 1; i <= M.n; i++) { for(j = 1; j <= M.n; j++) { scanf("%d", &y); Set(&M, i, j, y); } } Display(M); }

**Output:**

**Lower Triangular Matrix by Column Major Mapping Code in C++ Language:**

#include <iostream> using namespace std; class LowerTriangularMatrix { private: int *B; int n; public: LowerTriangularMatrix () { n = 3; B = new int[3 * (3 + 1) / 2]; } LowerTriangularMatrix (int n) { this->n = n; B = new int[n * (n + 1) / 2]; } ~LowerTriangularMatrix () { delete[]B; } int GetDimension () { return n; } void Set (int i, int j, int y); int Get (int i, int j); void Display (); }; void LowerTriangularMatrix::Set (int i, int j, int y) { if (i >= j) B[(n * (j - 1) - (j - 2) * (j - 1) / 2) + (i - j)] = y; } int LowerTriangularMatrix::Get (int i, int j) { if (i >= j) return B[(n * (j - 1) - (j - 2) * (j - 1) / 2) + (i - j)]; return 0; } void LowerTriangularMatrix::Display () { cout << "\nMatrix is: " << endl; for (int i = 1; i <= n; i++) { for (int j = 1; j <= n; j++) { if (i >= j) cout << B[(n * (j - 1) - (j - 2) * (j - 1) / 2) + (i - j)] << " "; else cout << "0 "; } cout << endl; } } int main () { int d; cout << "Enter Dimensions: "; cin >> d; LowerTriangularMatrix lm (d); int x; cout << "Enter All Elements: " << endl; for (int i = 1; i <= d; i++) { for (int j = 1; j <= d; j++) { cin >> x; lm.Set (i, j, x); } } lm.Display (); return 0; }

**Output:**

In the next article, I am going to discuss **Upper Triangular Matrix Row Major Mapping in C and C++ Language** with Examples. Here, in this article, I try to explain **Lower Triangular Matrix by Column Major Mapping in C and C++ Language** with Examples and I hope you enjoy this Lower Triangular Matrix by Column Major Mapping in C and C++ with Examples article.

**About the Author: Pranaya Rout**

Pranaya Rout has published more than 3,000 articles in his 11-year career. Pranaya Rout has very good experience with Microsoft Technologies, Including C#, VB, ASP.NET MVC, ASP.NET Web API, EF, EF Core, ADO.NET, LINQ, SQL Server, MYSQL, Oracle, ASP.NET Core, Cloud Computing, Microservices, Design Patterns and still learning new technologies.