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Strong Number Program in C# with Examples
In this article, I am going to discuss How to Implement the Strong Number Program in C# with Examples. Please read our previous article where we discussed the Buzz Number Program in C#. Here, in this article, first, we will learn what is a Strong Number and then we will see how to implement the Strong Number Program in C#. And finally, we will see how to print all the Strong numbers between a range of numbers like between 1 to 100 or 100 to 1000, etc.
What is a Strong Number?
A Strong number is a special number whose sum of the factorial of each digit is equal to the original number.
Examples:
Input: 145
Output: Yes, it is a strong number
Explanation: 1! + 4! + 5! = 145
Input: 124
Output: No, it is not a strong number
Explanation: 1! + 2! + 4! = 27 which is not equal to n i.e., 124
First of all, we have to know what is Factorial number. how it works. What is the basic method to solve this problem?
Factorial number: Factorial of n is the product of all positive descending integers.
For example
1) 5! = 5*4*3*2*1 = 120
2) 3! = 3*2*1 = 6
Factorial of Number in C#
using System; public class FactorialExample { public static void Main () { int i, fact = 1, n; Console.Write ("Enter any Number: "); n = int.Parse (Console.ReadLine ()); for (i = 1; i <= n; i++) { fact = fact * i; } Console.Write ("Factorial of " + n + " is: " + fact); } }
Output:
More Details: – https://dotnettutorials.net/lesson/factorial-program-in-csharp/
After understanding how to calculate the factorial of a number let’s come to our main question which is a strong number.
How to Implement Strong Number Program in C#?
Let us understand how to check whether a given number is a strong number or not in C#. The following are the steps that we need to follow to solve this problem.
- First, we take the input Number.
- Then we separate the individual number of digits.
- Then we calculate the factorial of the individual number of digits.
- After calculating factorial, we will sum the factorial of the individual digit.
Example: Strong Number in C#
The following sample code shows how to implement the strong number program in C#.
using System; public class StrongNumberProgram { public static void Main () { int number = 0, sum = 0; Console.WriteLine ("Enter a number"); number = Convert.ToInt32 (Console.ReadLine()); int quot = number; int remainder; while (quot != 0) { remainder = quot % 10; int fact = CalculateFactorial(remainder); quot = quot / 10; sum = sum + fact; } if(sum == number) { Console.WriteLine (number + " is a Strong Number"); } else { Console.WriteLine (number + " is not a Strong Number"); } } //Calulate Factorial of a number public static int CalculateFactorial(int number) { int fact = 1; for (int i = 1; i <= number; i++) { fact = fact * i; } return fact; } }
Output:
TIME COMPLEXITY: Time Complexity: O(N)
Print all strong number from 1 to N (input value from user)
Input: Number = 100
Output: 1 2
Explanation: Only 1 and 2 are the strong numbers from 1 to 100 because
1! = 1, and
2! = 2
Input: N = 1000
Output: 1 2 145
Explanation: Only 1, 2 and 145 are the strong numbers from 1 to 1000 because
1! = 1,
2! = 2, and
(1! + 4! + 5!) = 145
The idea is to iterate from [1, Number] and check if any number between that range is a strong number or not. If yes then print that number, else check for the next number.
C# Program to Print all Strong Numbers Between 1 and N
The following C# Program will allow the user to input a number and then it will print all the strong numbers between 1 and that input number.
using System; public class StrongNumberProgram { public static void Main () { int number = 0; Console.WriteLine ("Enter a number"); number = Convert.ToInt32 (Console.ReadLine()); int remainder; Console.WriteLine ("Strong Number Numbers Between 1 and "+ number + " : "); for(int i = 1; i<= number; i++) { int quot = i, sum = 0; while (quot != 0) { remainder = quot % 10; int fact = CalculateFactorial(remainder); quot = quot / 10; sum = sum + fact; } if(sum == i) { Console.Write(i + " "); } } } //Calulate Factorial of a number public static int CalculateFactorial(int number) { int fact = 1; for (int i = 1; i <= number; i++) { fact = fact * i; } return fact; } }
Output:
In the next article, I am going to discuss the Kaprekar Number Program in C# with Examples. Here, in this article, I try to explain How to Implement the Strong Number Program in C# with Examples and I hope you enjoy this article.