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Strong Number Program in C# with Examples
In this article, I am going to discuss How to Implement the Strong Number Program in C# with Examples. Please read our previous article where we discussed the Buzz Number Program in C#. Here, in this article, first, we will learn what is a Strong Number and then we will see how to implement the Strong Number Program in C#. And finally, we will see how to print all the Strong numbers between a range of numbers like between 1 to 100 or 100 to 1000, etc.
What is a Strong Number?
AĀ Strong number is a special number whose sum of the factorial of each digit is equal to the original number.Ā Ā
Examples:Ā Ā
Input: 145Ā Ā
Output: Yes, it is a strong numberĀ Ā
Explanation: 1! + 4! + 5! = 145Ā
Input: 124Ā Ā
Output: No, it is not a strong numberĀ Ā Ā
Explanation: 1! + 2! + 4! = 27 which is not equal to n i.e., 124Ā Ā
First of all, we have to know what is Factorial number. how it works. What is the basic method to solve this problem?Ā Ā
Factorial number:Ā Factorial of n is the product of all positive descending integers.Ā Ā
For exampleĀ Ā
Ā Ā Ā Ā Ā 1) 5! = 5*4*3*2*1 = 120Ā Ā Ā Ā
Ā Ā Ā Ā Ā 2) 3! = 3*2*1 = 6
Factorial of Number in C#Ā
using System;
public class FactorialExample
{
public static void Main ()
{
int i, fact = 1, n;
Console.Write ("Enter any Number: ");
n = int.Parse (Console.ReadLine ());
for (i = 1; i <= n; i++)
{
fact = fact * i;
}
Console.Write ("Factorial of " + n + " is: " + fact);
}
}
Output:
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More Details: –Ā https://dotnettutorials.net/lesson/factorial-program-in-csharp/Ā Ā
After understanding how to calculate the factorial of a number letās come to our main question which is a strong number.Ā
How to Implement Strong Number Program in C#?
Let us understand how to check whether a given number is a strong number or not in C#. The following are the steps that we need toĀ follow toĀ solve this problem.Ā Ā
- First, we take the input Number.Ā Ā
- Then we separate the individual number of digits.Ā Ā
- Then we calculate the factorial of the individual number of digits.Ā Ā
- After calculating factorial, we will sum the factorial of the individual digit.Ā
Example: Strong Number in C#
The following sample code shows how to implement the strong number program in C#.Ā
using System;
public class StrongNumberProgram
{
public static void Main ()
{
int number = 0, sum = 0;
Console.WriteLine ("Enter a number");
number = Convert.ToInt32 (Console.ReadLine());
int quot = number;
int remainder;
while (quot != 0)
{
remainder = quot % 10;
int fact = CalculateFactorial(remainder);
quot = quot / 10;
sum = sum + fact;
}
if(sum == number)
{
Console.WriteLine (number + " is a Strong Number");
}
else
{
Console.WriteLine (number + " is not a Strong Number");
}
}
//Calulate Factorial of a number
public static int CalculateFactorial(int number)
{
int fact = 1;
for (int i = 1; i <= number; i++)
{
fact = fact * i;
}
return fact;
}
}
Output:

TIMEĀ COMPLEXITY:Ā Time Complexity: O(N)Ā
Print all strong number from 1 toĀ N (input value from user)Ā
Input: Number = 100Ā Ā Ā
Output: 1 2Ā Ā Ā
Explanation: Only 1 and 2 are the strong numbers from 1 to 100 becauseĀ Ā Ā
1! = 1, andĀ Ā Ā
2! = 2Ā Ā
Input: N = 1000Ā Ā Ā
Output: 1 2 145Ā Ā Ā
Explanation:Ā Only 1, 2 and 145 are the strong numbers from 1 to 1000 becauseĀ Ā Ā
1! = 1,Ā Ā Ā
2! = 2, andĀ Ā Ā
(1! + 4! + 5!) = 145Ā Ā Ā
The idea is to iterate from [1, Number] and check if any number between that range is a strong number or not. If yes then print that number, else check for the next number.Ā Ā
C# Program to Print all Strong Numbers Between 1 and N
The following C# Program will allow the user to input a number and then it will print all the strong numbers between 1 and that input number.
using System;
public class StrongNumberProgram
{
public static void Main ()
{
int number = 0;
Console.WriteLine ("Enter a number");
number = Convert.ToInt32 (Console.ReadLine());
int remainder;
Console.WriteLine ("Strong Number Numbers Between 1 and "+ number + " : ");
for(int i = 1; i<= number; i++)
{
int quot = i, sum = 0;
while (quot != 0)
{
remainder = quot % 10;
int fact = CalculateFactorial(remainder);
quot = quot / 10;
sum = sum + fact;
}
if(sum == i)
{
Console.Write(i + " ");
}
}
}
//Calulate Factorial of a number
public static int CalculateFactorial(int number)
{
int fact = 1;
for (int i = 1; i <= number; i++)
{
fact = fact * i;
}
return fact;
}
}
Output:

In the next article, I am going to discuss the Kaprekar Number Program in C# with Examples. Here, in this article, I try to explain How to Implement the Strong Number Program in C# with Examples and I hope you enjoy this article.
